In a binary search tree, what is the worst-case height if the tree becomes degenerate?

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Multiple Choice

In a binary search tree, what is the worst-case height if the tree becomes degenerate?

Explanation:
Understanding how a binary search tree grows in the worst case: the height is the length of the longest path from the root to a leaf. If the tree becomes degenerate, each new element attaches to the end of the existing chain, making a single long path. This creates a structure that behaves like a linked list, so the longest path includes nearly all the nodes. As the number of nodes n grows, the height grows linearly with n, which is O(n). In such a degenerate tree, operations like search, insert, and delete can take linear time instead of the faster logarithmic time you’d get with a balanced BST.

Understanding how a binary search tree grows in the worst case: the height is the length of the longest path from the root to a leaf. If the tree becomes degenerate, each new element attaches to the end of the existing chain, making a single long path. This creates a structure that behaves like a linked list, so the longest path includes nearly all the nodes. As the number of nodes n grows, the height grows linearly with n, which is O(n). In such a degenerate tree, operations like search, insert, and delete can take linear time instead of the faster logarithmic time you’d get with a balanced BST.

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